Question

Question 8
Find the solution of the linear equation x + 2y = 8 which represent a point on:
(i) x-axis
(ii) y-axis

Answer 1

We have, x + 2y = 8 ….(i)
(i) When the point is on the x-axis, put y = 0 in Eq. (i). we get,
x + 2 $\times$ 0 = 8
$\Rightarrow$x = 8
Hence, the required point is (8, 0).
(ii)When the point is on the y-axis, put x = 0 in Eq(i). we get,
0 + 2y = 8
$\Rightarrow y=\frac{8}{2}=4$
Hence, the required point is (0, 4).