Question

Question 8. Two blocks of masses 10 kg and 20 kg are placed on the X-axis. The first mass is moved on the axis by a distance of 2 cm. By what distance should the second mass be moved to keep the position of the centre of mass unchanged?

Answer 1

Dear Student,


$$\begin{gathered} letthethecenterofmassbeinitiallybex \\ X=\frac{10X1+20X2}{30} \\ 10kgismovedby2cm.letitmovesaway2cm \\ letthenewpositionof20kgbeX\text{'}tokeepCM\hspace{0.17em}atX \\ X=\frac{10\left(X1+2\right)+20X\text{'}}{30} \\ 10X1+20X2=10X1+20+20X\text{'} \\ X2-X\text{'}=1cm \\ henceblockof20kgbedisplacedby1cm \\ REgards \end{gathered}$$