Question 8
Use Euclid’s division algorithm to find the HCF of 441, 567 and 693.
Let a = 693, b = 567 and c = 441
By Euclid's division algorithm,
a = bq + r [∵ dividend=divisor×quotient+remainder]
First, we take, a = 693 and b = 567. Find their HCF.
693=567×1+126
567=126×4+63
126=63×2+0
HCF (693, 567) = 63
Now to find the HCF of 441, 567 and 693, we find the HCF of 441 and the HCF of 563 and 697, which is 63, using Euclid's division aigorithm,
441 = 63×7+0
Since the remainder is 0, the HCF of 441 and 63 is 63.
Thus, HCF (693, 567, 441) = 63