Question 82 (vii)

Subtract

$- 3 p^{2} + 3 p q + 3 p x$ from 3p(-p-a-r)

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Solution

We have, $- 3 p^{2} + 3 p q + 3 p x$ and 3p(-p-a-r)
The required difference is given by
$3 p (- p - a - r) - (- 3 p^{2} + 3 p q + 3 p x) = - 3 p^{2} - 3 a p - 3 p r + 3 p^{2} - 3 p q - 3 p x$
$= (- 3 p^{2} + 3 p^{2}) - 3 a p - 3 p r - 3 p q - 3 p x = - 3 a p - 3 p r - 3 p q - 3 p x$
[grouping like terms]

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Subtract

$- 3 p^{2} + 3 p q + 3 p x$ from $3 p (- p - a - r)$

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