Question

Question 83 (xiv)

Multiply the following:
$-\frac{100}{9}rs;\frac{3}{4}{r}^3{s}^2$

Answer 1

We have,$\frac{-100}{9}rsand\frac{3}{4}{r}^3{s}^2$
$\therefore \frac{-100}{9}rs\times \frac{3}{4}{r}^3{s}^2=(\frac{-100}{9}\times \frac{3}{4})rs\times r^3{s}^2=\frac{-25}{3}\times r^4{s}^3$