Question 83 (xx)
Multiply the following:
(x2−5x+6),(2x+7)
We have (x2−5x+6) and (2x+7) ∴(x2−5x+6)(2x+7)=x2(2x+7)−5x(2x+7)+6(2x+7) =2x3+7x2−10x2−35x+12x+42=2x3−3x2−23x+42
Question 83 (vii)
7pqr, (p - q + r)