Question 83 (xxii)
Multiply the following:
(2x−2y−3),(x+y+5)
We have, (2x−2y−3) and (x+y+5)
∴(2x−2y−3)(x+y+5)=2x(x+y+5)−2y(x+y+5)−3(x+y+5)=2x2+2xy+10x−2yx−2y2−10y−3x−3y−15
=2x2+2xy−2yx+10x−3x−2y2−10y−3y−15 [grouping like terms]
=2x2+7x−13y−2y2−15