Question 85ivIf principal - Rs- 100000-Rate if interest - 10 Amount after one year-

Principal (P) = ₹ 100000 Rate of interest (R) = 10 % compounded half yearly nbsp;A = P( 1 + R/200)^n [for 6 months] ∴ A = P ( 1 + R/200)^n = 100000 ( 1 ...

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Standard VIII

Mathematics

Compounded Rate Half Yearly and Monthly

Question 85iv...

Question

Question 85(iv)

If principal = Rs. 100000,
Rate if interest = 10 % compounded half - yearly.
Amount after one year.

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Solution

Principal (P) = ₹ 100000
Rate of interest (R) = $10 %$ compounded half - yearly

$A = P (1 + \frac{R}{200})^{n} [f o r 6 m o n t h s]$
$∴ A = P (1 + \frac{R}{200})^{n} = 100000 (1 + \frac{10}{200})^{2} [∴ n = 2 f o r 12 m o n t h s]$
$= 100000 \times (\frac{21}{20})^{2} = 105000$

Amount after 12 months, i.e. one year = ₹110250

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Standard VIII Mathematics

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Question 85(iv) If principal = Rs. 100000, Rate if interest = 10 % compounded half - yearly. Amount after one year.

Principal (P) = ₹ 100000 Rate of interest (R) = 10 % compounded half - yearly A=P(1+R200)n [for 6 months] ∴ A=P (1+R200)n=100000 (1+10200 )2 [∴n=2 for 12 months] =100000×(2120)2=105000 Amount after 12 months, i.e. one year = ₹110250

Question 85(iv)

If principal = Rs. 100000,
Rate if interest = 10 % compounded half - yearly.
Amount after one year.