Question 85 (x)
Expand the following, using suitable identities.
(2x−5y)(2x−5y)
We have, (2x−5y)(2x−5y)=(2x−5y)2=(4x)2+(5y)2−2×2x×5y [using the identity, (a−b)2=a2+b2−2ab]=16x2+25y2−20xy
Question 85 (vii)
(2x+9)(2x−7)
Question 85 (xiv)
(7x+5)2
Question 85 (i)
(xy+yz)2
Question 85 (ix)
(2x3−23)(2x3+2a3)