Question 85 (xiv)
Expand the following, using suitable identities.
(7x+5)2
We have, (7x+5)2=(7x)2+52+2×7x×5=49x2+25+70x [using the identity, (a+b)2=a2+b2+2ab]
Question 85 (vii)
(2x+9)(2x−7)
Question 85 (v)
(45p+53q)2
Question 85 (x)
(2x−5y)(2x−5y)
Question 85 (i)
(xy+yz)2