Question 86 (ii)
Using suitable identities, evaluate the following:
(49)2
We have, (49)2=(50−1)2 =(50)2+12−2×50×1 [using the identity, (a−b)2=a2+b2−2ab] =2500+1−100=2401
Question 86 (i)
(52)2
Question 86 (iii)
(103)2
Question 86 (iv)
(98)2
Question 86 (xiii)
(9.9)2