Question 86 (iii)
Using suitable identities, evaluate the following:
(103)2
We have, (103)2=(100+3)2=(100)2+32+2×100×3=10000+9+600 =10609 [using the identity, (a+b)2=a2+b2+2ab]
Question 86 (ii)
(49)2
Question 86 (i)
(52)2
Question 86 (vii)
47×53
Question 86 (xii)
98×103