Question 86 (v)
Using suitable identities, evaluate the following:
(1005)2
We have, (1005)2=(1000+5)2=(1000)2+52+2×1000×5=1000000+25+10000 =1010025 [using the identity, (a+b)2=a2+b2+2ab]
Question 86 (vii)
47×53
Question 86 (xiii)
(9.9)2
Question 86 (ii)
(49)2
Question 86 (xx)
(339)2−(161)2