Question 86 (xi)

Using suitable identities, evaluate the following:

$101 \times 103$

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Solution

We have,
$101 \times 103 = (100 + 1) (100 + 3) = (100)^{2} + (1 + 3) 100 + 3 \times 1 = 10000 + 400 + 3$
$= 10403$ [using the identity, $(x + a) (x + b) = x^{2} + (a + b) x + a b$ ]

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Question 86 (xi)

Using suitable identities, evaluate the following:

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Question 86 (iii)

Using suitable identities, evaluate the following:

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