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Question

Question 86 (xv)

Using suitable identities, evaluate the following:

10.1×10.2


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Solution

We have,
10.1×10.2=(10+0.1)(10+0.2)=(10)2+(0.1+0.2)10+(0.1)(0.2)=100+0.3×10+0.02
=103.02 [using the identity, (x+a)(x+b)=x2+(a+b)x+ab]


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