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Question

Question 88 (xvi)

Factorise the following expression.

(ax2ybxyzax2z+bxy2

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Solution

We have, (ax2ybxyzax2z+bxy2
=x(axybyzaxz+by2)
=x(axyaxzbyz+by2)
=x[ax(yz)+by(z+y)]
=x[(ax+by)(yz)]

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