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Question

Question 88 (xvii)

Factorise the following expression.

a2b+a2c+ab+ac+b2c+c2b

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Solution

We have, a2b+a2c+ab+ac+b2c+c2b
=(a2b+ab+b2c)+(a2c+ac+c2b)
=b(a2+a+bc)+c(a2+a+bc)
=(a2+a+bc)(b+c)

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