Question 88 (xviii)

Factorise the following expression.

$2 a x^{2} + 4 a x y + 3 b x^{2} + 2 a y^{2} + 6 b x y + 3 b y^{2}$

Open in App

Solution

We have $2 a x^{2} + 4 a x y + 3 b x^{2} + 2 a y^{2} + 6 b x y + 3 b y^{2}$
$= (2 a x^{2} + 2 a y^{2} + 4 a x y) + (3 b x^{2} + 3 b y^{2} + 6 b x y)$
$= 2 a (x^{2} + y^{2} + 2 x y) + 3 b (x^{2} + y^{2} + 2 x y)$
$= (2 a + 3 b) (x + y)^{2}$

Suggest Corrections

Similar questions

Question 92 (xviii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$a^{4} - (a - b)^{4}$

\to E = (4 a x y \sqrt{z})^i + (2 a x^{2} \sqrt{z})^j + (\frac{a x^{2} y}{\sqrt{z}})^k

a

6 a b + 12 b c

(- x y - a y)

l^{2} m^{2} n - l m^{2} n^{2} - l^{2} m n^{2}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program