CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

(a + b)^2 = a^2 + 2ab +b^2

Question 88 x...

Question

Question 88 (xviii)

Factorise the following expression.

$2 a x^{2} + 4 a x y + 3 b x^{2} + 2 a y^{2} + 6 b x y + 3 b y^{2}$

Open in App

Solution

We have $2 a x^{2} + 4 a x y + 3 b x^{2} + 2 a y^{2} + 6 b x y + 3 b y^{2}$
$= (2 a x^{2} + 2 a y^{2} + 4 a x y) + (3 b x^{2} + 3 b y^{2} + 6 b x y)$
$= 2 a (x^{2} + y^{2} + 2 x y) + 3 b (x^{2} + y^{2} + 2 x y)$
$= (2 a + 3 b) (x + y)^{2}$

Suggest Corrections

thumbs-up

10

Similar questions

Question 92 (xviii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$a^{4} - (a - b)^{4}$

Q. The electric field in a region is given by:

\to E = (4 a x y \sqrt{z})^i + (2 a x^{2} \sqrt{z})^j + (\frac{a x^{2} y}{\sqrt{z}})^k

a

is a positive constant. The equation of an equipotential surface will be of the form

Q. Question 88 (i)

Factorise the following expression.

6 a b + 12 b c

Q. Question 88 (ii)

Factorise the following expression.

(- x y - a y)

Q. Question 88 (iv)

Factorise the following expression.

l^{2} m^{2} n - l m^{2} n^{2} - l^{2} m n^{2}

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

(a + b)^2 = a^2 + 2ab +b^2

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon