Question 89 (x)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$16 x^{2} + 40 x + 25$

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Solution

We have, $16 x^{2} + 40 x + 25$
$= (4 x)^{2} + 2.4 x .5 + 5^{2} = (4 x + 5)^{2} = (4 x + 5) (4 x + 5)$

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Question 92 (x)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

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Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$ :

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