CameraIcon

SearchIcon

MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Factorisation of Algebraic Expressions Using Identities

Question 89 x...

Question

Question 89 (x)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$16 x^{2} + 40 x + 25$

Open in App

Solution

We have, $16 x^{2} + 40 x + 25$
$= (4 x)^{2} + 2.4 x .5 + 5^{2} = (4 x + 5)^{2} = (4 x + 5) (4 x + 5)$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Question 90 (x)

Factorise the following, using the identity,

a^{2} - 2 a b + b^{2} = (a - b)^{2}

\frac{x^{2}}{4} - 2 x + 4

Q. Question 89 (vii)

Factorise the following, using the identity,

a^{2} + 2 a b + b^{2} = (a + b)^{2}

a^{2} x^{2} + 2 a b x + b^{2}

Question 92 (x)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$49 x^{2} - 36 y^{2}$

Q. Question 89 (v)

Factorise the following, using the identity,

a^{2} + 2 a b + b^{2} = (a + b)^{2}

4 x^{2} + 4 x + 1

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$ :

$9 x^{2} + 2 x y + \frac{y^{2}}{9}$

Join BYJU'S Learning Program

explore_more_icon

Explore more

Factorisation of Algebraic Expressions Using Identities

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon