Question 92y-5-3-26-3-y

2y+5/3=26/3 y ⇒ 2y+y=26/3 5/3 ⇒ 3y=26 5/3 ⇒ 3y=21/3 ⇒ y=21/3 × 3=7/3 To check : 2y+5/3=26/3 y ⇒ 2 ×7/3+5/3=26/3 7/3 ⇒14/3+5/3=26/3 7/3⇒14+5/3=26 7/3 ⇒19/3=19/3 ...

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Standard X

Mathematics

Dividendo

Question 92y+...

Question

Question 9
$2 y + \frac{5}{3} = \frac{26}{3} - y$

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Solution

$2 y + \frac{5}{3} = \frac{26}{3} - y$
$\Rightarrow 2 y + y = \frac{26}{3} - \frac{5}{3}$
$\Rightarrow 3 y = \frac{26 - 5}{3}$
$\Rightarrow 3 y = \frac{21}{3}$
$\Rightarrow y = \frac{21}{3 \times 3} = \frac{7}{3}$
To check :
$2 y + \frac{5}{3} = \frac{26}{3} - y \Rightarrow 2 \times \frac{7}{3} + \frac{5}{3} = \frac{26}{3} - \frac{7}{3}$
$\Rightarrow \frac{14}{3} + \frac{5}{3} = \frac{26}{3} - \frac{7}{3} \Rightarrow \frac{14 + 5}{3} = \frac{26 - 7}{3}$
$\Rightarrow \frac{19}{3} = \frac{19}{3}$
$\Rightarrow L . H . S = R . H . S$
Hence, it is correct.

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Q. Question 9

2 y + \frac{5}{3} = \frac{26}{3} - y

The lines = 2, = 5, y = 3 & y = –4 form a rectangle. Find equations of its diagonals.

If $2 y + \frac{5}{3} = \frac{26}{3} - y$ , then $y = ?$

(a) $1$

(b) $\frac{2}{3}$

(d) $\frac{7}{3}$

Q. Question 5(vii)
Factorise the expressions and divide them as directed

39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)

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Question 9 2y+53=263−y

2y+53=263−y ⇒2y+y=263−53 ⇒3y=26−53 ⇒3y=213 ⇒y=213×3=73 To check : 2y+53=263−y⇒2×73+53=263−73 ⇒143+53=263−73⇒14+53=26−73 ⇒193=193 ⇒L.H.S=R.H.S Hence, it is correct.

Question 9
$2 y + \frac{5}{3} = \frac{26}{3} - y$