Question 9 (i)
100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:
Number of lettersNumber of surnames1−464−6306−8448−121612−204
(i) Draw a histogram to depict the given information.
Question 9 (i)
100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:
Number of lettersNumber of surnames1−464−6306−8448−121612−204
(i) Draw a histogram to depict the given information.
(i) Here, it can be observed that the data has class intervals of varying width. The proportion of the number of surnames per 2 letters interval can be calculated as follows.
Number ofFrequency (Number of surnames)Width of classLength of rectangle1−4636×23=44−630230×22=306−844244×22=448−1216416×24=812−20484×28=1
By taking the number of letters on x-axis and the proportion of the number of Surnames per 2 letters interval on y-axis and choosing an appropriate scale (1unit = 4 students for y axis), the histogram can be constructed as follows.
(i) Here, it can be observed that the data has class intervals of varying width. The proportion of the number of surnames per 2 letters interval can be calculated as follows.
Number ofFrequency (Number of surnames)Width of classLength of rectangle1−4636×23=44−630230×22=306−844244×22=448−1216416×24=812−20484×28=1
By taking the number of letters on x-axis and the proportion of the number of Surnames per 2 letters interval on y-axis and choosing an appropriate scale (1unit = 4 students for y axis), the histogram can be constructed as follows.
