Question

Question 9
The additive inverse of $\frac{-7}{19}$ is:
(a) $\frac{-7}{19}$
(b) $\frac{7}{19}$
(c) $\frac{19}{7}$
(d) $\frac{-19}{7}$

Answer 1

We know that, if a and b are the additive inverse of each other, then a + b = 0
Suppose, x is the additive inverse of $\frac{-7}{19}$
Then, $x-\frac{7}{19}=0\Rightarrow x=\frac{7}{19}$
Hence, additive inverse of $\frac{-7}{19}$ is $\frac{7}{19}$ i.e option (b)