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Rational Numbers

Question 9The...

Question

Question 9
The additive inverse of $\frac{- 7}{19}$ is:
(a) $\frac{- 7}{19}$
(b) $\frac{7}{19}$
(c) $\frac{19}{7}$
(d) $\frac{- 19}{7}$

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Solution

We know that, if a and b are the additive inverse of each other, then a + b = 0
Suppose, x is the additive inverse of $\frac{- 7}{19}$
Then, $x - \frac{7}{19} = 0 \Rightarrow x = \frac{7}{19}$
Hence, additive inverse of $\frac{- 7}{19}$ is $\frac{7}{19}$ i.e option (b)

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Similar questions

The additive inverse of $\frac{- 7}{19}$ is:
(a) $\frac{- 7}{19}$
(b) $\frac{7}{19}$
(c) $\frac{19}{7}$
(d) $\frac{- 19}{7}$

Question 5

In the following question out of the four options only one is correct, write the correct answer:

If $\frac{5 x}{3} - 4 = \frac{2 x}{5},$ then the numerical value of 2x-7 is:

(a) $\frac{19}{13}$

(b) $\frac{- 13}{19}$

(c) 0

(d) $\frac{13}{19}$

Q. Verify the following:
(i) 19 × {7 + (−3)} = 19 × 7 + 19 × (−3)
(ii) (−23) {(−5) + (+19)} = (−23) × (−5) + (−23) × (+19)

Q. Find the additive inverse of each of the following:
(i)

\frac{1}{3}

\frac{23}{9}

(iii) −18
(iv)

\frac{- 17}{8}

\frac{15}{- 4}

\frac{- 16}{- 5}

\frac{- 3}{11}

\frac{19}{- 6}

\frac{- 8}{- 7}

Q. 7, 19, 11, 19, 15, 15, 19, 11

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Rational Numbers

Standard VII Mathematics

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