Question 90 (i)

Factorise the following, using the identity, $a^{2} - 2 a b + b^{2} = (a - b)^{2}$

$x^{2} - 8 x + 16$

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Solution

We have,
$x^{2} - 8 x + 16 = x^{2} - 2. x .4 + 4^{2} = (x - 4)^{2} [∵ a^{2} - 2 a b + b^{2} = (a - b)^{2}] = (x - 4) (x - 4)$

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Question 92 (i)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$x^{2} - 9$

a^{2} - 2 a b + b^{2} = (a - b)^{2}

4 a^{2} - 4 a b + b^{2}

a^{2} - 2 a b + b^{2} = (a - b)^{2}

a^{2} y^{3} - 2 a b y^{2} + b^{2} y

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