Question 90 (iv)

Factorise the following, using the identity, $a^{2} - 2 a b + b^{2} = (a - b)^{2}$ .

$p^{2} - 2 p + 1$

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Solution

We have,
$p^{2} - 2 p + 1 = p^{2} - 2. p .1 + 1^{2} = (p - 1)^{2} = (p - 1) (p - 1)$

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Question 92 (iv)

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