CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Zero Exponent

Question 91So...

Question

Question 91

Solve the following.
$(i) 100^{- 10} (i i) 2^{- 2} \times 2^{- 3} (i i i) {(\frac{1}{2})}^{- 2} \div {(\frac{1}{2})}^{- 3}$

Open in App

Solution

(i) $100^{- 10} = {(\frac{1}{100})}^{10}$
(ii) $2^{- 2} \times 2^{- 3}$
$= 2^{- 2 - 3} = 2^{- 5}$
$= {(\frac{1}{2})}^{5} = \frac{1}{32}$
(iii) ${(\frac{1}{2})}^{- 2} \div {(\frac{1}{2})}^{- 3}$
$= {(\frac{1}{2})}^{- 2 + 3} = {(\frac{1}{2})}^{1} = \frac{1}{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Question 91

Solve the following.
$(i) 100^{- 10} (i i) 2^{- 2} \times 2^{- 3} (i i i) {(\frac{1}{2})}^{- 2} \div {(\frac{1}{2})}^{- 3}$

Question 3(iii)
Find the value of:

${(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}$

Q. Study the following pattern:

1 =

\frac{1 \times 2}{2}

\frac{2 \times 3}{2}

\frac{3 \times 4}{2}

1 + 2 + 3 + 4 =

\frac{4 \times 5}{2}

By observing the above pattern, find

(i) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

(ii) 50 + 51 + 52 + ................ + 100

(iii) 2 + 4 + 6 + 8 + 10 + ............... + 100

Find the value of:

$(1) (2^{0} + 3^{- 1}) \times 3^{2}$

$(i i) (2^{- 1} \times 3^{- 1}) \div 2^{- 3}$

$(i i i) {(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}$

Q. Find the value of:
(i) (2⁰ + 3⁻¹) × 3²
(ii) (2⁻¹ × 3⁻¹) ÷ 2⁻³
(iii)

{(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon