Question 91 (xiii)

Factorise the following:

$p^{2} - 16 p - 80$

Open in App

Solution

We have, $p^{2} - 16 p - 80$
$p^{2} - (20 - 4) p - 80 = p^{2} - 20 p + 4 p - 80 = p (p - 20) + 4 (p - 20) = (p - 20) (p + 4)$

Suggest Corrections

Similar questions

p^{2} - 16 p - 80

p^{2} - 13 p - 30

Question 91 (iv)

Factorise the following:

$p^{2} + 14 p + 13$

(a^{3} x - x^{4} + a^{2} x^{2} - a x^{3})

a^{2} + 2 a b + b^{2} = (a + b)^{2}

2 x^{3} + 24 x^{2} + 72 x

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program