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Factorisation of Quadratic Polynomials

Question 92 v...

Question

Question 92 (viii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{2}}{9} - \frac{y^{2}}{25}$

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Solution

We have,
$\frac{x^{2}}{9} - \frac{y^{2}}{25} = {(\frac{x}{3})}^{2} - {(\frac{y}{5})}^{2} = (\frac{x}{3} - \frac{y}{5}) (\frac{x}{3} + \frac{y}{5})$

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Similar questions

Question 92 (i)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$x^{2} - 9$

Question 92 (viii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{2}}{9} - \frac{y^{2}}{25}$

Question 92 (ix)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{2 p^{2}}{25} - 32 q^{2}$

Question 92 (xi)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

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Question 92 (xv)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{3} y}{9} - \frac{x y^{3}}{16}$

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Factorisation of Quadratic Polynomials

Standard X Mathematics

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