Question 92 (xi)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$y^{3} - \frac{y}{9}$

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Solution

$y^{3} - \frac{y}{9} = y (y^{2} - \frac{1}{9}) = y [y^{2} - {(\frac{1}{3})}^{2}] = y (y + \frac{1}{3}) (y - \frac{1}{3})$

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Question 92 (xi)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$y^{3} - \frac{y}{9}$

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