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Factorisation of Quadratic Polynomials

Question 92 x...

Question

Question 92 (xvii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{1}{36} a^{2} b^{2} - \frac{16}{49} b^{2} c^{2}$

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Solution

$\frac{1}{36} a^{2} b^{2} - \frac{16}{49} b^{2} c^{2} = {(\frac{a b}{6})}^{2} - {(\frac{4 b c}{7})}^{2} = (\frac{a b}{6} + \frac{4 b c}{7}) (\frac{a b}{6} - \frac{4 b c}{7}) = b^{2} (\frac{a}{6} + \frac{4 c}{7}) (\frac{a}{6} - \frac{4 c}{7})$

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Factorisation of Quadratic Polynomials

Standard X Mathematics

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