Question 94 (iii)
Carry out the following division:
17ab2c3÷(−abc2)
We have, 17ab2c3÷(−abc2)=17ab2c3(−abc2)=17×a×b×b×c×c×c−a×b×c×c=−17bc
Question 94 (ii)
76x3yz3÷19x2y2
Question 94 (i)
51x3y2z ÷ 17xyz
Question 94 (iv)
−121p3q3r3÷(−11xy2z3)