Question

Question 94

Solve the following:

The sum of four consecutive integers is 266. What are the integers?

Answer 1

Let the four consecutive integers be x, x+1, x+2 and x+3.
According the question,
x+x+1+x+2+x+3=266
$\Rightarrow 4x+6=266\Rightarrow 4x=266-6\Rightarrow 4x=260\Rightarrow x=\frac{260}{4}\therefore x=65$
Hence, the four consecutive integers are 65, 65+1, 65+2 and 65+3, i.e 65, 66, 67 and 68.