Question

Question 95

Solve the following:

Express $\frac{16}{81}and\frac{-16}{81}$ as powers of rational number.

Answer 1

$\because 16=4\times 4=4^{2}and81=9\times 9=9^2\therefore \frac{16}{81}=\frac{(4{)}^2}{(9{)}^2}={\left(\frac{4}{9}\right)}^{2}and\frac{-16}{81}=\frac{-(4{)}^2}{(9{)}^2}=-{\left(\frac{4}{9}\right)}^2$