Question

Question) A closed rectangular wooden box has inner dimensions 90 cm by 80 cm by 70 cm. Compute its capacity and the area of the tin foil needed to line its inner surface.

Answer 1

Dear student
$$\begin{gathered} 1)\mathrm{Capacity}\mathrm{of}\mathrm{box}=\mathrm{lbh}=90\times 80\times 70=504000{\mathrm{cm}}^3 \\ \mathrm{Surface}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{tin}\mathrm{foil}\mathrm{needed}\mathrm{to}\mathrm{line}\mathrm{its}\mathrm{inner}\mathrm{surface}=2\left(\mathrm{lb}+\mathrm{bh}+\mathrm{hl}\right) \\ =2\left[\left(90\times 80\right)+\left(80\times 70\right)+\left(70\times 90\right)\right] \\ =2\left[7200+5600+6300\right] \\ =38200{\mathrm{cm}}^2 \end{gathered}$$
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