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Question) A signal frequency 12 kHz and peak voltage 12 V is used to modulate a carrier of frequency 1 MHz and peak voltage 24 V. What is the modulation index and the produced sidebands ? [0.5, 1012 kHz, 988 kHz]

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Solution

Dear Student,

$f_{s} = 12 k H z, V_{s} = 12 v, f_{c} = 1 M H z, V_{c} = 24 v m o d u l a t i o n I n d e x m = \frac{12}{24} = 0.5 s i d e b a n d e r r o r . = \pm 12 K H z U p b a n d = 1000 K H z + 12 K H z = 1012 K H z d o w n b a n d = 1000 K H z - 12 K H z = 988 k H z R e g a r d s$

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