Question) Find the volume, surface area and length of diagonal of a cube of an edge 4.5 cm.

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Solution

$Length of the edge of cube, s = 4.5 cm Volume of cube = s^{3} = {(4.5)}^{3} = 91.125 {cm}^{3} surface area of cube = 6 s^{2} = 6 \times {(4.5)}^{2} = 6 \times 121.5 {cm}^{2} Length of the diagonal = \sqrt{3} s = 1.732 \times 4.5 = 7.794 cm$

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Question) Find the volume, surface area and length of diagonal of a cube of an edge 4.5 cm.

Length of the edge of cube, s = 4.5 cmVolume of cube = s3 = 4.53 = 91.125 cm3surface area of cube = 6s2 = 6 × 4.52 = 6 × 121.5 cm2Length of the diagonal = 3s = 1.732 × 4.5 = 7.794 cm

$Length of the edge of cube, s = 4.5 cm Volume of cube = s^{3} = {(4.5)}^{3} = 91.125 {cm}^{3} surface area of cube = 6 s^{2} = 6 \times {(4.5)}^{2} = 6 \times 121.5 {cm}^{2} Length of the diagonal = \sqrt{3} s = 1.732 \times 4.5 = 7.794 cm$