Q. The standard state Gibbs free energies of formation of
C(graphite) and
C(diamond) at
T=298 K are
ΔfG∘C(graphite)=0kJ mol−1
ΔfG∘C(diamond)=2.9kJ mol−1
The standard state means that the pressure should be 1 bar, and substance should be pure at a given temperature. The conversion of graphite
C(graphite) to diamond C(diamond) reduces its volume by 2×10−6m3mol−1. If C(graphite) is converted to C(diamond) isothermally at T=298 K, the pressure at which C(graphite) is in equilibrium with C(diamond), is?
[Useful information: 1 J=1 kgm2s−2;1 Pa=1 kg m−1s−2;1 bar=105Pa]
- 29001 bar
- 14501 bar
- 1450 bar
- 58001 bar