JIPMER | 2015

- 3×105J
- 4×106J
- 2.08×106J
- None of these

View Solution

(Density of mercury =13.6g/cm3 , Density of water=1 g/cm3, Surface tension of Mercury =484.5 dyne/cm, Surface tension of water=72.7dyne/cm)

- 5.9
- 4.9
- 2.9
- 1.9

View Solution

- 4.3×104N/m2
- 1.8×107N/m2
- 2.1×105N/m2
- 3.7×104N/m2

View Solution

- 12√2
- 0.6
- 12√3
- 1√2

View Solution

- 5800 K
- 8000 K
- 6700 K
- 7800 K

View Solution

- 2.5Ω
- 1.25Ω
- 5Ω
- 103Ω

View Solution

The amplitude of resultant motion is

- √x20−s20+2x0s0
- x0+s0+2x0s0
- [x20+s20+√2x0s0]1/2
- √x20+s20

View Solution

- 2GMm3a2
- 7GMm√2a2
- 3GMma2
- √3GMm8a2

View Solution

- 2π√km
- 12π√km
- 2π√mk
- 12π√mk

View Solution

The resistance of pair of rods is (ρAl=2.6×10−8Ω−m and ρCu=1.7×10−8Ω−m)

- 1.0 m Ω
- 3.0 m Ω
- 2.0 m Ω
- None of these

View Solution

- 2.1×10−3Ω
- 1.3×10−4Ω
- 3.2×10−4Ω
- 4.6×10−2Ω

View Solution

x=t2(2−t3)

The distance between A and B (in μm) is closed to

- 10.7
- 20.7
- 40.7
- 50.7

View Solution

- h=H2
- h=3H2
- h=2H3
- h=34H

View Solution

- 3cl+2Dl23(2c+Dl)
- 2cl+3Dl22(4c+8l)
- 2cl+3Dl23(2c+l)
- cl+Dl23(2c+Dl)

View Solution

- 30 m/s
- 42 m/s
- 46 m/s
- 50 m/s

View Solution

- 500 J
- 700 J
- 600 J
- 900 J

View Solution

If the sphere rolls without slipping, then the acceleration with which the centre of sphere moves, is

- F2m
- 3F7m
- 10F7m
- 7F2m

View Solution

- ρ2ρ1=eMω2l22RT
- ρ1ρ2=eMωl2RT
- ρ1ρ2=eωlM3RT
- ρ2ρ1=eM2ω2l23RT

View Solution

- 4.5×105A
- 3.2×10−5A
- 9.9×10−2A
- 6.7×10−4A

View Solution

- cos−1(13)
- cos−1(−13)
- sin−1(13)
- sin−1(−13)

View Solution

- 483
- 504
- 377
- 346

View Solution

- 27MV
- 18MV
- 20MV
- 23MV

View Solution

- 7.6×102Jkg−1
- 2.4×104Jkg−1
- 3.6×104Jkg−1
- 4.9×104 Jkg−1
- 7.9×104 Jkg−1

View Solution

- 0.97 cm−3
- 0.66 cm−3
- 0.59 cm−3
- 0.15 cm−3

View Solution

- 4.0×10−4N
- 2.0×10−5N
- 3.5×10−6N
- 2.0×10−9N

View Solution

- 50 N
- 26 N
- 29 N
- 45.9 N

View Solution

- 0.1 m
- 10 cm
- 1 cm
- 0.01 cm

View Solution

- ucosθsecα
- u2cos2αsin2α
- ucosθ.tanα
- usinθ.sinα

View Solution

- 0.125 A
- 1.67 A
- 0.13 A
- 0.67 A

View Solution

- μ0i(b−a)θ4πab
- μ0i(b−a)π−θ
- μ0i(a−b)2πab
- μ0i(b−a)θπab

View Solution