Q. In Wheatstone's bridge, three resistors P, Q, R are connected in three arms in order and
4th arm S is formed by two resistors
s1 and
s2 connected in parallel. The condition for bridge to be balanced is:
PQ=- R(s1+s2)s1s2
- Rs1s2(s1+s2)
- s1s2R(s1+s2)
- (s1+s2)Rs1s2