Quick lime CaO is produced by heating limestone CaCO3 to drive off CO2 gas- CaCO3 s - CaO s -CO2 g - H0-180 KJ- - S0-150 J-K-Assuming the variation of enthalpy change and entropy change with temperature to be negligible- choose the incorrect options-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Enthalpy

Quick lime ...

Question

Quick lime $(C a O)$ is produced by heating limestone $(C a C O_{3})$ to drive off $C O_{2}$ gas.
$C a C O_{3} (s) \to C a O (s) + C O_{2} (g), Δ H^{0} = 180 K J; Δ S^{0} = 150 J / K .$

Assuming the variation of enthalpy change and entropy change with temperature to be negligible, choose the incorrect option(s).

Decomposition of

C a C O_{3}

(s) is never spontaneous.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Decomposition of

C a C O_{3}

(s) becomes spontaneous when temperature is less than

900^{0} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Decomposition of

C a C O_{3}

(s) becomes non-spontaneous when temperature is greater than

1000^{0} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Decomposition of

C a C O_{3}

(s) becomes spontaneous when temperature is greater than

927^{0} C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D Decomposition of $C a C O_{3}$ (s) becomes spontaneous when temperature is greater than $927^{0} C$ .
$T = \frac{Δ H}{Δ S} = \frac{180 \times 10^{3}}{150} = 1200 K .$
Temperature $= 1200 - 273 = 927^{0} C$
For $Δ G < 0, T > 927^{0} C$ .

Suggest Corrections

Similar questions

Q. Quick lime (CaO) is produced by heating limestone

(C a C O_{3})

to drive off

C O_{2}

gas.

C a C O_{3} (s) \to C a O (s) + C O_{2} (g), Δ H^{o} = 180 K J, Δ S^{o} = 150 J / K

Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option.

Q. In conversion of lime-stone to lime,

C a C O_{3} (s) \to C a O (s) + C O_{2} (g)

, the values of

Δ^{0} H

and

Δ S^{0}

are

+ 179.1 k J m o l^{- 1}

and

160.2 J / K m o l

respectively at

298 K

and

1

bar. Assuming that

Δ H^{o}

and

Δ S^{o}

do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is:

Q. In conversion of limestone to lime,

C a C O_{3 (s)} \to C a O_{(s)} + C O_{2 (g)}

; the values of

Δ H^{0}

and

Δ S^{0}

are + 179.1 kJ/mol and 160.2J/K respectively, at 298K and 1 bar. Above what temperature, conversion of limestone to lime will be spontaneous (assuming that

Δ H^{0}

and

Δ S^{0}

do not change with temperature)?

Q. In the conversion of limestone to lime,

C a {C O}_{3} (s) \to C a O (s) + {C O}_{2} (g)

the values of

Δ H^{o}

and

Δ S^{o}

are

+ 179.1 k J {m o l}^{- 1}

and

160.2 k J {m o l}^{- 1}

respectively at

298 K

and

1

bar. Assuming that,

Δ H^{o}

and

Δ S^{o}

do not change with temperature; temperature above which conversion of limestone to lime will be spontaneous is:

In concersion of lime-stone to lime,

$C a C O_{3} (s) \to C a O (s) + C O_{2} (g)$ the values of $Δ H^{0}$ and $Δ S^{0}$ are $+ 179.1 k J m o l^{- 1}$ and $160.2 J / K$ respectively at 298 K and 1 bar. Assuming that $Δ H^{0}$ and $Δ S^{0}$ do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is

Join BYJU'S Learning Program

Quick lime (CaO) is produced by heating limestone (CaCO3) to drive off CO2 gas.CaCO3(s)→CaO(s)+CO2(g),ΔH0=180KJ;ΔS0=150J/K.Assuming the variation of enthalpy change and entropy change with temperature to be negligible, choose the incorrect option(s).

The correct option is D Decomposition of CaCO3(s) becomes spontaneous when temperature is greater than 9270C.T=ΔHΔS=180×103150=1200K.Temperature =1200−273=9270C For ΔG<0,T>9270C.

The correct option is D Decomposition of $C a C O_{3}$ (s) becomes spontaneous when temperature is greater than $927^{0} C$ .
$T = \frac{Δ H}{Δ S} = \frac{180 \times 10^{3}}{150} = 1200 K .$
Temperature $= 1200 - 273 = 927^{0} C$
For $Δ G < 0, T > 927^{0} C$ .