Electric Field inside a Conductor under Electrodynamic Conditions
r1 = 1 mr2 = ...
Question
r1=1m r2=2m r3=3m
Figure shows some equipotential surfaces [Spherical in shape]
A
Electric field in the region is directed radialy outwards.
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B
Magnitude of electric field is E=6r
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C
Magnitude of electric field is E=6r2
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D
Electric field decreases as we move radialy outwords.
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Solution
The correct option is B Magnitude of electric field is E=6r Let E=crn by dV=−→E.→dr ∫110dv=−∫21crndr⇒9=Cr+1(2n+1−1) ---(1) ∫−1410dv=∫31crndr⇒24=Cn+1(3n+1−1) ---(2)
By (2) ÷ (1) ⇒83=(3n+1−1)(2n+1−1)
By hit and trial n = 1
By (1) ⇒9=C2(22−1)
C = 6
So E = 6r