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Other Synthesis Methods

R1- C ≡ N + R...

Question

$R_{1} - C \equiv N + R_{2} M g B r (i) D r y e t h e r - ------ \to (i i) H_{3} O^{+} 1 - p h e n y l - 1 - p r o p a n o n e$
$R_{1}$ and $R_{2}$ groups are respectively:

A

R_{1} = C_{2} H_{5}; R_{2} = C_{6} H_{5}

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B

R_{1} = C_{6} H_{5}; R_{2} = C H_{3}

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C

R_{1} = C_{6} H_{5}; R_{2} = C_{6} H_{5}

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D

R_{1} = C H_{3}; R_{2} = C_{6} H_{5}

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Solution

The correct option is A $R_{1} = C_{2} H_{5}; R_{2} = C_{6} H_{5}$
$R_{1} = C_{2} H_{5}; R_{2} = C_{6} H_{5}$

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R_{1} - C \equiv N + R_{2} M g B r (i) D r y e t h e r - ------ \to (i i) H_{3} O^{+} 1 - p h e n y l - 1 - p r o p a n o n e

R_{1}

R_{2}

groups are respectively:

R_{1} - C \equiv N + R_{2} M g B r (i) D r y e t h e r - ------ \to (i i) H_{3} O^{+} 1 - p h e n y l - 1 - p r o p a n o n e

R_{1}

R_{2}

groups are respectively:

Q. Assertion :In a

△ A B C

a < b < c

r

is inradius and

r_{1}, r_{2}, r_{3}

are the axradii opposite to angle

A, B, C

respectively, then

r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

Q. Two particles 'A' and 'B', move with constant velocities

_{1}

_{2}

respectively. At the initial moment, their position vectors are

_{1}

_{2}

respectively. The condition for particle 'A' and 'B' for their collision is

Q. The radii of described circle of

△ A B C

r_{1}, r_{2}

r_{3}

respectively (opposite to vertices

A, B

C

r_{2} + r_{3} = 2 R

r_{1} + r_{2} = 3 R

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