In the adjoining figure, chord AB and diameter CD of a circle with centre O meet at P. PT is a tangent to the circle at T. If AP =16 cm , AB =12 cm and DP =2 cm, find the radius of the circle.

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Componendo and Dividendo

In the adjoin...

Question

r = 15

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r = 20

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r = 25

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r = 10

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Solution

The correct option is A
r = 15

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Similar questions

5 x^{2} + 15 x + 10

\sum_{r = 2}^{25} \frac{1}{(r^{2} - 1)}

A = (16 x + 8) + 4

B = (15 x - 10) + - 5

A - B

5^{- p} = 4^{- q} = 20^{r}

\frac{1}{p} + \frac{1}{q} + \frac{1}{r} =

\sqrt{5 x - 5} + \sqrt{10 x - 5} = \sqrt{15 x - 10}

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