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Question

R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x - 3. Then, R−1 is


A

{(8, 11), (10, 13)}

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B

{(11, 8), (13, 10)}

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C

{(10, 13), (8, 11), (12, 10)}

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D

None of these

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Solution

The correct option is A

{(8, 11), (10, 13)}


R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x - 3

Now, we have :

11- 3 = 8

13 - 3 = 10

So, R = {(13, 10), (11, 18)}

R1= {(10, 13), (8, 11)}


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