R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x - 3. Then, R−1 is
{(8, 11), (10, 13)}
R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x - 3
Now, we have :
11- 3 = 8
13 - 3 = 10
So, R = {(13, 10), (11, 18)}
∴R−1= {(10, 13), (8, 11)}