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Question

R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x − 3. Then, R−1 is
(a) {(8, 11), (10, 13)}
(b) {(11, 8), (13, 10)}
(c) {(10, 13), (8, 11)}
(d) none of these

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Solution

(a) {(8, 11), (10, 13)}

The relation R is defined by
R=x, y : x11, 12, 13, y8, 10, 12 : y = x-3R=11, 8, (13, 10)So, R-1=8, 11, 10, 13

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