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Question

Radiation coming from transition n = 2 to n = 1 of hydrogen atoms falls on helium ions in n = 1 and n = 2 states. What are the possible transitions of helium ions as they absorbs energy from the radiation?

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Solution

Energy of radiation (E) from the hydrogen atom is given by
E=13.61n12-1n22
Hydrogen atoms go through transition, n = 1 to n = 2.
The energy released is given by
E=13.611-14 =13.6×34=10.2 eV
For He,
Atomic no, Z = 2
Let us check the energy required for the transition in helium ions from n = 1 to n = 2.

∴ n1 = 1 to n2 = 2

Energy E1 of this transition is given by
E1=Z213.61n12-1n22 =4×13.6 1-14 =40.8 eV
E1 > E,
Hence, this transition of helium ions is not possible.

Let us check the energy required for the transition in helium ion from n = 1 to n = 3.
∴ n1 = 1 to n2 = 3

EnergyE2 for this transition is given by
E2=Z2×13.6 1n22-1n12 =4×13.6×11-19 =48.3 eV
It is clear that E2 > E.
Hence, this transition of helium ions is not possible.

Similarly, transition from n1 = 1 to n2 = 4 is also not possible.

Let us check the energy required for the transition in helium ion from n = 2 to n = 3.
∴ n1 = 2 to n2 = 3
Energy E3 for this transition is given by
E3=13.6×4 14-19 =20×13.636=7.56 eV

Let us check the energy required for the transition in helium ion from n = 2 to n = 3.
∴ n​​1 = 2 to n2 = 4
Energy E4 for this transition is given by
E4=13.6×4 14-116 =13.6×34=10.2 eV

We find that
E3 < E
E4 = E
Hence, possible transitions are from n = 2 to n = 3 and n = 2 to n = 4.

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