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Question

Radiation from a hydrogen discharge tube with energy of photons 13.6 eV goes through a filter which transmits only waves of wavelength greater than 4400 ˚A and is incident on a metal of work function 2.0 eV. Its stopping potential is n×102 V. The value of n is (integer only)
[Use hc=12400 eV (˚A)]

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Solution

Given, E13.6 eV ; λ=4400 ˚Aϕ0=2.0 eV ; hc=12400 eV (˚A)

From, Einstein's photoelectric equation,

E=ϕ0+eV0

(Eϕ0)×1e=V0

V0=(hcλϕ0)×1e

=(12400 eV˙A4400 ˙A2 eV)×1e

=(1.24×10444002)

=0.818182×102 V

n=82

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