Radiation of wavelength $242$ nm is sufficient to ionize the sodium atom. Calculate the ionization of energy in kJ mol $^{- 1}$ . ( $n = 6.625 \times 10^{- 24}$ J-s).

594.57 K J m o l^{- 1}

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494.57 K J m o l^{- 1}

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694.57 K J m o l^{- 1}

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394.57 K J m o l^{- 1}

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Solution

The correct option is A $494.57 K J m o l^{- 1}$
$I E = \frac{h c}{λ} = (\frac{6.625 \times 10^{- 34} \times 3 \times 10^{8}}{242 \times 10^{- 9}} \times N_{A})$
$= 494657$ joule/mol
$= 494.65$ Kj/mol

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Similar questions

Q. Radiation of wavelength 242 nm is sufficient to ionise the sodium atom. Calculate the ionization energy in

k J m o l^{- 1}

. (

h = 6.625 \times 10^{- 34} J - s

)

An electromagnetic radiation of wavelength 242 nm is just sufficient to ionize a sodium atom. Calculate the ionization energy of sodium in kJ ${m o l}^{- 1}$ .

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. Calculate the ionisation energy of sodium in kJ $m o l^{- 1}$ .

Electromagnetic radiations of wavelength 242 nm is just sufficient to ionize Sodium atom. Then the ionization energy of Sodium in kJ mole⁻¹ is

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Radiation of wavelength 242 nm is sufficient to ionize the sodium atom. Calculate the ionization of energy in kJ mol−1. (n=6.625×10−24J-s).

The correct option is A 494.57 KJmol−1IE=hcλ=(6.625×10−34×3×108242×10−9×NA) =494657 joule/mol =494.65 Kj/mol

Radiation of wavelength $242$ nm is sufficient to ionize the sodium atom. Calculate the ionization of energy in kJ mol $^{- 1}$ . ( $n = 6.625 \times 10^{- 24}$ J-s).

The correct option is A $494.57 K J m o l^{- 1}$
$I E = \frac{h c}{λ} = (\frac{6.625 \times 10^{- 34} \times 3 \times 10^{8}}{242 \times 10^{- 9}} \times N_{A})$
$= 494657$ joule/mol
$= 494.65$ Kj/mol