Question

Radii of the top and the base of a frustum are 12 cm, 6 cm respectively. Its height is 8 cm. Then the volume of the frustum is _____$c{m}^3.$ (Use =$\pi =\frac{22}{7}$)

• A. 1200
• B. 1508
• C. 2112
• D. 2715

Answer 1

The correct option is C 2112

Given, Radii of the frustum of the cone $r_1=12cm$
$r_2=6cm$
Height of the frustum of the cone h = 8 cm

Volume of the frustum of the cone $=\frac{1}{3}\pi h(r_1^2+r_2^2+r_1{r}_2)$
$=\frac{1}{3}\times \frac{22}{7}\times \left(8\right)\times ({12}^2+6^2+(12\left)\right(6\left)\right)$
$=2112c{m}^3$